Question

8.00 L of sulfur hexafluoride gas are heated from 225K to 350K. If the pressure and number of gas particles do not change, what is the new volume after the temperature increase? 1.00 x 103 L 1.02 x 10-4 L 12.4 L 5.14 L

Answer 1

12.4L

Step-by-step explanation:

Given parameters:

T₁ = 225K

T₂ = 350K

V₁ = 8L

Unknown:

V₂ = ?

Solution:

Since this heating takes place under constant pressure, we can resolve this temperature and volume relationship using Charles's law.

According to this law "the volume of a gas is directly proportional to the temperature provided that pressure is constant".

Mathematically, we have;

`(V_(1) )/(T_(1) ) = (V_(2) )/(T_(2) )`

Input the parameters and solve for the unknown;

`(8)/(225) = (V_(2) )/(350)`

V₂ = 12.4L