Question

Chords AC and BD intersect at E, with BD = 7 units, DE = 2 units, and AE = 4 units.

What is the length of segment CE?

Answer 1

2.5

Explanation:

Got it right

Answer 2

Answer: CE IS 2.5 UNITS

BD=7 units

DE=2 units

AE=4 units

BE=BD-DE=7-2=5 units

By the intersecting chord theorem (when two chords intersect each other inside a circle then the products of their segments are equal )

5/4=x/2

5*2/4=x

10/4=x

2.5=x

CE is 2.5 units