183k views
2 votes
Write the standard equation of a circle that passes through (1, −6) with center (7, −2).

A: (x + 1)2 + (y – 6)2 = 52


B: (x + 7)2 + (y – 2)2 = 52


C: (x – 1)2 + (y + 6)2 = 52


D: (x – 7)2 + (y + 2)2 = 52

User Jer
by
6.6k points

2 Answers

3 votes

Answer: (x – 7)2 + (y + 2)2 = 52

User Abelyao
by
7.1k points
0 votes

Answer:

D: (x – 7)2 + (y + 2)2 = 52

Explanation:

Circle: (x -h)² + (y - k)² = r² center (h , k) r: radius

(1 , -6) on the circle: radius √(1 - 7)² + (-6 - (-2))² = √36 + 16 = √52

(x -7)² + (y +2)² = (√52)² = 52

User Rob Horton
by
6.7k points