Question

Write the standard equation of a circle that passes through (1, −6) with center (7, −2).

A: (x + 1)2 + (y – 6)2 = 52


B: (x + 7)2 + (y – 2)2 = 52


C: (x – 1)2 + (y + 6)2 = 52


D: (x – 7)2 + (y + 2)2 = 52

Answer 1

Answer: (x – 7)2 + (y + 2)2 = 52

Answer 2

D: (x – 7)2 + (y + 2)2 = 52

Explanation:

Circle: (x -h)² + (y - k)² = r² center (h , k) r: radius

(1 , -6) on the circle: radius √(1 - 7)² + (-6 - (-2))² = √36 + 16 = √52

(x -7)² + (y +2)² = (√52)² = 52