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The distance d in feet that a dropped odie tu falls in t seconds is given by the square d divided 16=t^2.How long does it take a dropped object to fall 64 feet

User Matin H
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1 Answer

6 votes

Answer:

The correct answer is 16 seconds for the body to fall 64 feets.

Explanation:

The equation of a dropped odie tu falling is given by
(d^(2))/(16) = t^(2) where d is the distance in feet and t is the time it took in seconds.

Now an object falls from 64 feet. The time it takes to fall is given by


(64^(2))/(16) =
t^(2)

⇒ t = ±
(64)/(4) = 16.

Negative sign is neglected as time cannot be negative.

Thus it would take 16 seconds for the object to drop from 64 feets.

User Martney Acha
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