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An open rectangular tank of length 0.2m and breadth 0.15m contains water to a height of 0.16m.Find the surface area of the tank that is in contact with the water.

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Answer:

0.172 square meter of the tank's surface area is in contact with the water.

Explanation:

Given:

The dimensions of the water tank are:

Length = 0.2 m.

Width = 0.15 m.

Height = 0.16 m.

Now, to find the area of surface of the tank which is in contact with water.

So, to get the surface area of tank we put formula:


Surface\ area=2(length* width + width* height + height* length)\\\\Surface\ area=2(0.2* 0.15+0.15* 0.16+0.16* 0.2)\\\\Surface\ area=2(0.03+0.024+0.032)\\\\Surface\ area=2(0.086)\\\\Surface\ area=2* 0.086\\\\Surface\ area=0.172\ square\ meter.

Hence, the surface area of the tank is 0.172 square meter.

Therefore, 0.172 square meter of the tank's surface area is in contact with the water.

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