Question

Exactly 50.0mL of HOCl solution of unknown concentration was titrated with 0.100 mol NaOH. An end point was reached when 38.5mL of the base was added. Calculate the molar concentration of the HOCl soluion.

Answer 1

To find the molarity of the HOCl solution, we first determined the moles of NaOH used in the titration and then calculated the molarity of HOCl to be 0.0770 M, assuming a 1:1 reaction ratio between HOCl and NaOH.

Step-by-step explanation:

To calculate the molarity of the HOCl solution, we need to know the molar amounts of NaOH used and that the titration reaction is assumed to be 1:1 since HOCl behaves similarly to HCl in reactions with NaOH. To find the moles of NaOH, we use the volume and concentration:

Moles of NaOH = Volume in L × Molarity

= 0.0385 L × 0.100 M

= 0.00385 moles

Since the number of moles of HOCl will be the same at the endpoint of the titration, the concentration of the HOCl solution can be calculated as:

Molarity of HOCl = Moles of HOCl / Volume of HOCl solution in L

= 0.00385 moles / 0.0500 L

= 0.0770 M

Answer 2

Molarity of HOCl =0.87 mol/Litre

Step-by-step explanation:

It is a acid base titration after completion of reaction salt and water.

At the end point of raction,

mili equivalent of HOCl = Mili equivalent of NaOH;

`normality = molarity* n-factor`

`N_1* V_1=N_2* V_2`

n-factor for HOCL and NaOH is 1 for both

hence

normality = molarity;

molarity of
`NaOH=(mole)/(volume of solution in litre)`

`molarity =(0.1Mol)/(0.0885L) = Normality=N_2`

`N_1 *50=(0.1)/(0.0885) *38.5`

`N_1=0.87`;

Molarity of HOCl =0.87 mol/Litre