67.4k views
2 votes
1) Luis hizo una excursión de 20 km 75 hm 75 dam 250 m en tres etapas. En la primera recorrió 5 km 5hm, y en la segunda 1 km 50 dam más que en la anterior. a) ¿Cuánto recorrió en la tercera etapa? b) Expresa el resultado en metro

User Halim
by
7.9k points

1 Answer

4 votes

Answer:

21500 m

Explanation:

We will divide this point into four parts and we will pass it by the meter:

Total: (20 km * 1000 m / 1 km) + (75 hm * 100 m / 1 hm) + (75 dam * 10 m / 1 dam) + 250 m = 20000 m + 7500 m + 750 m + 250 m = 28500 m

First stage: (5 km * 1000 m / 1 km) + (5 hm * 100 m / 1 hm) = 5000 m + 500 m = 5500 m

Second stage: (1 km * 1000 m / 1 km) + (50 dam * 10 m / 1 dam) = 1000 m + 500 m = 1500 m

The value of the third stage would be the subtraction between the total and the first and second stage:

Third stage: 28500 m - 5500 m - 1500 m = 21.500 m

He traveled 21500 meters in the third stage

User John Landahl
by
8.4k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories