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Find two consecutive numbers less than 100, for the first of which the sum of the digits is 8, and the second is divisible by 8.

User Sino Raj
by
6.0k points

1 Answer

2 votes

Answer:

80 and 81.

Explanation:

To find two consecutive numbers less than 100 that satisfy the given conditions, we can follow these steps:

1. Start by finding the first number:

- Since the sum of the digits should be 8, we can list the possible combinations:

- 17 (1 + 7 = 8)

- 26 (2 + 6 = 8)

- 35 (3 + 5 = 8)

- 44 (4 + 4 = 8)

- 53 (5 + 3 = 8)

- 62 (6 + 2 = 8)

- 71 (7 + 1 = 8)

- 80 (8 + 0 = 8)

- Out of these combinations, we need to find the one where the second number is divisible by 8.

- The only combination that satisfies this condition is 80.

2. The first number is 80. Now, let's find the second number:

- Since the numbers are consecutive, we add 1 to the first number: 80 + 1 = 81.

Therefore, the two consecutive numbers less than 100 that satisfy the given conditions are 80 and 81.

User Irwan Madness
by
6.4k points
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