Question

A block of ice weighs 500 N. What is the minimum work is required to push it up a 6 m long incline that rises 3m?

Answer 1

The work done in lifting the weight on an inclined plane is 2598N

Step-by-step explanation:

Given:

Weight, W = 500N

Distance, s = 6m

`sin \alpha = (Perpendicular)/(hypotenuse)`

Where,

Perpendicular = 3m

Hypotenuse = 6m

Substituting the value:

`sin \alpha = (3)/(6) \\\\sin \alpha = (1)/(2) \\\\\alpha = 30^o`

Work done = F X scosα

`W = 500 X 6 X cos(30)\\\\W = 3000 X (√(3) )/(2) \\\\\\W = 1500√(3) \\\\W = 2598N`

Therefore, work done in lifting the weight on an inclined plane is 2598N