Question

PLEASE ANSWER!

A chamber with a fixed volume is shown above. The temperature of the gas inside the chamber before heating is 25.2 C and it’s pressure is 0.600 atm. The gas is heated with a flame to a temperature of 72.4 C, what is it’s pressure at this temperature

Answer 1

Answer:0.695

Step-by-step explanation:

Answer 2

0.7atm

Step-by-step explanation:

Given parameters:

Initial temperature = 25.2°C in Kelvin; 25.2 + 273 = 298.2K

Initial pressure = 0.6atm

Final temperature = 72.4°C in kelvin = 72.4 + 273 = 345.4K

Unknown:

Final pressure = ?

Solution:

Since we are dealing with pressure temperature relationships under a fixed volume, we use a simplification of the combined gas law to solve this problem.

At fixed volume;

`(P_(1) )/(T_(1) ) = \frac{P_(2) }{_T{2} }`

where P and T are temperature values

1 and 2 are the initial and final states

Input the parameters and solve for P₂

`(0.6)/(298.2) = (P_(2) )/(345.4)`

P₂ = 0.7atm