Answer:
cos(theta) = 3sqrt(58)/58
sin(theta) = 7sqrt(58)/58
Explanation:
Cos(2theta) = 2cos²(theta) - 1
-20/29 = 2cos²(theta) - 1
2cos²(theta) = 9/29
cos²(theta) = 9/58
cos(theta) = sqrt(9/58)
cos(theta) = 3sqrt(58)/58
sin²(theta) = 1 - cos²(theta)
sin²(theta) = 1 - 9/58
sin²(theta) = 49/58
sin(theta) = sqrt(49/58)
sin(theta) = 7sqrt(58)/58
sqrt: square root