Question

What is the energy of a radio wave photon with a frequency of 1.255 x 106 sec-1 ?

a. 1.202 x 10^ 27 J
b. 239.0 J
c. 8.316 x 10^-28 J
d. 1.255 J
e. 1.255 x 10^-19 J

Answer 1

The correct answer is option c.

Step-by-step explanation:

`E=h\\u =(h* c)/(\lambda)`

where,

E = energy of photon = ?

h = Planck's constant =
`6.63* 10^(-34)Js`

`\\u` =- frequency of the wave

c = speed of light =
`3* 10^8m/s`

`\lambda` = wavelength of the radio wave photon

Now put all the given values in the above formula, we get the energy of the photons.

`E=6.63* 10^(-34)Js* 1.255* 10^6 s^(-1)`

`E=8.316* 10^(-28)J`

Hence, the correct answer is option c.