Question

In ΔBCD, the measure of ∠D=90°, CB = 37, BD = 12, and DC = 35. What is the value of the sine of ∠B to the nearest hundredth?

Answer 1

Answer: or it’s 0.34

Explanation:

Answer 2

`Sine \ B\approx 0.95`

Explanation:

-We use the Law of Sines to find the Sine of ∠B.

-We notice that ∠B corresponds to length DC=35.

#We therefore calculate the Sine of ∠B as follows:

`(a)/(Sin \ A)=(b)/(Sin \ B)\\\\(37)/(Sin \ 90\textdegree)=(35)/(Sin \ B)\\\\=>Sin \ 90\textdegree=1\\\\\therefore Sin \ B=(35)/(37)\\\\=0.9459\approx0.95`

Hence, the Sine of ∠B is approximately 0.95