Question

What is the vertex of g(x)=3(x+1)^2-12

Answer 1

(-1,-12)

Explanation:

This equation is in vertex form

g(x)=a(x-h)^2+k where( h,k) is the vertex

g(x)=3(x+1)^2-12

Rewriting

g(x)=3(x- -1)^2+ -12

So the vertex is

(-1,-12)