Answer:
Explanation:
hello :
y=|x−3|+|x+2|−|x−5|, if x<−2
if x<−2 :
x-3 ≤ 0 so : |x−3| = - (x-3) = 3-x
x+2 ≤ 0 so : |x+2| = - (x+2) = -x-2
x-5≤ 0 so : |x−5| = -(x-5) = 5-x
y=(3-x)+(-x-2)−(5-x) = 3-x-x-2-5+x
y = -x - 4
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