Question

what is the 60th term in an arithmetic sequence with the first term equal 1 and the constant difference equals 7​

Answer 1

Answer: 60th term of sequence is 414

Step-by-step explanation: An = a + (n-1)d

Here n=60, a=1, d=7

A60 = 1+(60–1)7

A60 = 1+(59)7

A60= 1+413

A60 = 414

Hence 60th term of sequence is 414