Question

I need fast help with step by step

`\int\limits^2_1 {(3x-1)/(x+1) } \, dx`

Answer 1

1.38 to the nearest hundredth.

Explanation:

Dividing:

x + 1 ) 3x - 1 ( 3

3x + 3

-4

so (3x - 1) / (x + 1) = 3 - 4 / x+ 1

Integral of (3 - 4 / x+1 ) = 3x - 4 ln(x + 1)

Between limits of 1 and 2 we have:

(3(2) - 4 ln 3) - (3 - 4 ln2)

= 1.6056 - 0.2274

= 1.3782.