Question

`NH_(4)Cl` and
`NaNO_(3)`

Balanced Equation

Total Ionic Equation

Net Ionic Equation

Answer 1

a) Balanced equation

NH₄Cl (aq) + NaNO₃ (aq) → NH₄NO₃ (s) + NaCl (aq)

b) Total Ionic Equation

NH₄⁺(aq) + Cl⁻(aq) + Na⁺(aq) + NO₃⁻(aq) → NH₄NO₃(s) + Na⁺(aq) + Cl⁻(aq)

c) Net Ionic Equation

NH₄⁺ (aq) + NO₃⁻ (aq) → NH₄NO₃(s)

Answer 2

Balanced Equation = NH₄Cl₍aq₎ + NaNO₃₍aq₎ = NH₄NO₃₍aq₎+ NaCl₍aq₎

Total Ionic Equation = NH₄⁺Cl⁻₍aq₎ + Na⁺NO₃⁻₍aq₎ = NH₄⁺NO₃⁻₍aq₎+ Na⁺Cl⁻₍aq₎

Net iconic equation= NH₄⁺₍aq₎ + NO₃⁻₍aq₎ = NH₄⁺NO₃⁻₍aq₎

Step-by-step explanation:

Balanced Equation = NH₄Cl₍aq₎ + NaNO₃₍aq₎ = NH₄NO₃₍aq₎+ NaCl₍aq₎

Total Ionic Equation = NH₄⁺Cl⁻₍aq₎ + Na⁺NO₃⁻₍aq₎ = NH₄⁺NO₃⁻₍aq₎+ Na⁺Cl⁻₍aq₎

NH₄⁺+Cl⁻₍aq₎ + Na⁺+NO₃⁻₍aq₎ = NH₄⁺+NO₃⁻₍aq₎+ Na⁺+Cl⁻₍aq₎

Cl⁻₍aq₎ cancels each other from both sides

NO₃⁻cancels each other from both sides

Net iconic equation is the remaining from the Total Ionic Equation after NO₃⁻ and Cl⁻₍aq₎ cancels each other from both sides

Net iconic equation= NH₄⁺₍aq₎ + NO₃⁻₍aq₎ = NH₄⁺NO₃⁻₍aq₎