Question

`AlCl_(3)` and NaOH

Balanced Equation

Total Ionic Equation

Net Ionic Equation

Answer 1

a) Balanced equation

AlCl₃ (aq) + 3NaOH (aq) → 3NaCl (aq) + Al(OH)₃ (s)

b) Total Ionic Equation

Al³⁺(aq) + 3Cl⁻(aq) + 3Na⁺(aq) + 3OH⁻(aq) → 3Na⁺(aq) + 3Cl⁻(aq) + Al(OH)₃(s)

c) Net Ionic Equation

Al³⁺(aq) + 3OH⁻(aq) → Al(OH)₃(s)

Answer 2

Step-by-step explanation:

Balanced Equation is 2ALCL₃₍ₐq₎ + 6NaOH₍ₐq₎ = 2Al(OH)₃₍s₎ + 6NaCl₍ₐq₎

Total Iconic Equation is AL²⁺+2CL₃⁻ + 6Na⁺+ 6(OH)⁻= Al²⁺(OH)₃⁻ + 6Na⁺+6Cl⁻

2CL₃⁻ cancels 6Cl⁻ from both sides

6Na⁺ cancels 6Na⁺ from both sides

the Net Ionic Equation is AL²⁺ ₍ₐq₎+ 6(OH)⁻₍ₐq₎= Al²⁺(OH)₃⁻₍s₎