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If x increased by the product of 11 and y is 103, and 9x increased by the product of 10 and y is 126, what are the values of x and y?

A. x= 8y=5
B. x = 9.y = 12
C. X= 4, y = 9
D. x = 9, y = 4

1 Answer

4 votes

Answer:

C. x=4,y=9

Explanation:

The given information show that

x+11y=103 (1)

9x+10y=126 (2)

Isolate x from (1)

x=103-11y

Substitute x=103-11y into (2)

9(103-11y)+10y=126

927-99y+10y=126

-89y=-801

y=9

So x=103-11x9=4

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