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Solve a=b+3c−2 for c.

Solve a=b+3c−2 for c.
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4 votes
Solve a=b+3c−2 for c.

User Pizycki
by
8.5k points

1 Answer

3 votes

Answer:

(a-b+2)/3 = c

Explanation:

a=b+3c−2

Add 2 to each side

a+2=b+3c−2+2

a+2 = b+3c

Subtract b from each side

a+2 -b =3c

Divide each side by 3

(a-b+2)/3 = 3c/3

(a-b+2)/3 = c

User Lonnie
by
8.8k points
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