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Stan Luo · Answer 1 · 2021-04-01T01:56:41+0000

Answer:

Answer is given below with explanations.

Explanation:

$given \: ab \: is \: parallel \: to \: dc \\ by \:corollary \: of thales \: theorem \\ (ab )/(dc) = (be)/(dc) = (ae)/(de) \\ hence \: triangle \: abe \: is \: similar \: to \: triangle \: dce$

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