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Can someone please help me answer my last question?


f(x)=(√(2x+8))/(x^(2)-2x )

To find the domain of the function in the interval notation

User NOr
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1 Answer

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Well we have a function and its body is a fraction so we need to handle those edge cases, namely division by 0.

That means solving the following equation,


x^2-2x=0\implies x(x-2)\implies x_1=0,x_2=2.

As we can see x must not be equal to 0 or 2 if we do not want to end up with division by zero situation.

The domain is therefore
\mathbb{R}-\{0,2\}.

Writing this as interval would be,


x\in(-\infty,0)\cup(0,2)\cup(2,\infty).

Hope this helps.

User Paul Cezanne
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