Question

What volume of a .0100MAGNO3 solution is required to completely react with the CACL2 in 3.00L of a 0.1 00 MCAL to solution with balanced chemical equation is

Answer 1

Answer : The volume of
`AgNO_3` required is, 60 L

Explanation :

First we have to calculate the moles of
`CaCl_2`

`\text{Moles of }CaCl_2=\text{Concentration of }CaCl_2* \text{Volume of solution}`

`\text{Moles of }CaCl_2=0.100M* 3.00L=0.3mol`

Now we have to calculate the moles of
`AgNO_3`

The balanced chemical reaction will be:

`2AgNO_3+CaCl_2\rightarrow 2AgCl+Ca(NO_3)_2`

From the balanced chemical reaction we conclude that,

As, 1 mole of
`CaCl_2` completely react with 2 moles of
`AgNO_3`

So, 0.3 mole of
`CaCl_2` completely react with
`0.3* 2=0.6` moles of
`AgNO_3`

Now we have to calculate the volume of
`AgNO_3` required.

`\text{Volume of }AgNO_3=\frac{\text{Moles of }AgNO_3}{\text{Concentration of }AgNO_3}`

`\text{Volume of }AgNO_3=(0.6mol)/(0.0100M)=60L`

Therefore, the volume of
`AgNO_3` required is, 60 L