Question

The gas begins with a temperature of 333 K and a pressure of 4.00 atm that increases to 7.65 atm as the gas is heated. What is the temperature of the gas when the pressure increases to 7.65 at?

Answer 1

The final temperature on increasing the pressure to 7.65 atm is 637 K.

Step-by-step explanation:

The relation between temperature attained by gas molecules at varying pressure is defined by Guy-Lusac's law. It states that at constant volume, the pressure experienced by the gas molecules is directly proportional to the temperature attained by those molecules.

P∝T

Here, the initial pressure P₁ is given as 4 atm at temperature T₁ = 333 K, then the final pressure P₂ = 7.65 atm can be attained at temperature T₂.

The final temperature should be greater than the initial temperature as there is an increase in the pressure.

So,

`(P_(1) )/(T_(1) ) = (P_(2) )/(T_(2) )`

`(4)/(333) =(7.65)/(T_(2) ) \\\\T_(2) =(7.65*333)/(4) = 636.8 =637 K`

Hence, the final temperature on increasing the pressure to 7.65 atm is 637 K.