Answer:
(x, y) = (80, 40)
Explanation:
Since the x-factor is squared, its relative contribution to the sum will be twice that of the y-factor. The two numbers are (x, y) = (80, 40).
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There are several ways to work this problem. One is to express y in terms of x, then maximize the resulting function of x.
y = 120 -x
f(x,y) = y(x^2)
f(x) = (120 -x)(x^2) = -x^3 +120x^2
Then the derivative of the product with respect to x is this.
f'(x) = -3x^2 +240x
We want to set that equal to zero and find the corresponding value of x.
-3x(x -80) = 0
x = 0 or 80
Since the leading coefficient of the cubic is negative, we know the smallest x-value will correspond to a minimum. We want the maximum, so we want ...
x = 80
y = 120 -80 = 40
The two real numbers of interest are (x, y) = (80, 40).