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Select the equation that represents a problem that opens down from a vertex of (32,26) and has a focus located 20 units away from the vertex

User Velixo
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1 Answer

2 votes

Answer:

Explanation:

If the parabola opens downward, and we have a p value (which is the distance from the vertex to the focus), the form of the equation we need is:


-(x-h)^2=4p(y-k)

If the vertex is (32, 26), then h = 32 and k = 26. If the focus is located 20 units from the vertex, then p = 20. Filling in:


-(x-32)^2=4(20)(y-26) and


-(x-32)^2=80(y-26) and


-(1)/(80)(x-32)^2=y-26 so the equation is


-(1)/(80)(x-32)^2+26=y

You didn't give choices so I'm not sure what form you need this in. This is vertex (or work) form.

User Niiru
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