Question

A 12-V battery is connected to a device and 24 mA (24 x 10' Amps) of current flows

through it. If the device obeys Ohm's law, how much current will flow when a 24-V battery
is used?

Answer 1

According to Ohm's law, the current through a device is directly proportional to the voltage and inversely proportional to its resistance. The current flowing through the device when a 24-V battery is used would be 48 mA.

Step-by-step explanation:

According to Ohm's law, the current flowing through a device is directly proportional to the voltage applied across it and inversely proportional to its resistance. In this case, when a 12-V battery is connected and 24 mA of current flows, we can use Ohm's law to find the resistance of the device. The resistance (R) can be calculated using the formula R = V/I, where V is the voltage and I is the current. So, R = 12 V / 0.024 A = 500 ohms.

Now, if a 24-V battery is used, we can again use Ohm's law to find the new current. The resistance of the device remains the same (500 ohms), so the current (I) can be calculated using the formula I = V/R, where V is the voltage and R is the resistance. So, I = 24 V / 500 ohms = 0.048 A or 48 mA.

Answer 2

Correct answer: Ic₂ = 48 mA = 48 · 10⁻³ A

Step-by-step explanation:

Given:

U₁ = 12 V DC first battery voltage

Ic₁ = 24 mA = 24 · 10⁻³ A Intensity of current with the first battery

U₂ = 24 V DC second battery voltage

Ic₂ = ? Intensity of current with the second battery

The formula that applies to a simple electric circuit under the Ohm's law is:

R = U / Ic

where R is the total resistance in the electrical circuit and it is constant.

R = U₁ / Ic₁ = U₂ / Ic₂ ⇒ U₁ / Ic₁ = U₂ / Ic₂ ⇒ Ic₂ = (U₂ · Ic₁) / U₁

Ic₂ = (24 · 24) / 12 = 48 mA

Ic₂ = 48 mA = 48 · 10⁻³ A

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