Question

On the picture to the right,

AB and AC are segments tangent to circle k(O). OB=3 cm, and OA =6 cm.
Find AB, AC, m∠3, and m∠4.

Answer 1

AB&AC= sqrt27, m<3=30˚, m<4=30˚

Explanation:

6^2-3^2= 27, BA & CA= sqrt27

90˚&60˚&30˚ makes a right triangle

angles 3&4 are less than the non-labeled angles, so they have to be 30˚

Answer 2

AB = 5.2

AC = 5.2

m∠3 = 30 degrees

, m∠4 = 30 degrees

Explanation:

Triangle ABO and ACO are both 30 60 90 triangles and are equal

Therefore If we have two sides then we can figure out the last side