Answer:
AB&AC= sqrt27, m<3=30˚, m<4=30˚
Explanation:
6^2-3^2= 27, BA & CA= sqrt27
90˚&60˚&30˚ makes a right triangle
angles 3&4 are less than the non-labeled angles, so they have to be 30˚
AB = 5.2
AC = 5.2
m∠3 = 30 degrees
, m∠4 = 30 degrees
Triangle ABO and ACO are both 30 60 90 triangles and are equal
Therefore If we have two sides then we can figure out the last side
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