Question

Well I'm having troubles with something I have no idea what it is or how to do it. The problem is x^2 -18x+8=0. I only know how to set it up. I know that you group the x^2=0 and -18x+8=0

Answer 1

`x = (-(-18) -√((-18)^2 -4*1*8))/(2) = (18 -2 √(73))/(2)= 9 -√(73)`

`x = (-(-18) +√((-18)^2 -4*1*8))/(2) = (18 +2 √(73))/(2)= 9 +√(73)`

Explanation:

We have the following equation:

`x^2 -18 x +8 =0`

We can use the quadratic formula given by:

`x = (-b \pm √(b^2 -4ac))/(2a)`

Where:

`a = 1 , b=-18, c =8`

And replacing we got:

`x = (-(-18) -√((-18)^2 -4*1*8))/(2) = (18 -2 √(73))/(2)= 9 -√(73)`

`x = (-(-18) +√((-18)^2 -4*1*8))/(2) = (18 +2 √(73))/(2)= 9 +√(73)`