Question

A rectangle has an area of 72 square feet and a lengh 8 times greater than its width. what is the perimeter of the rectangle​

Answer 1

Explanation:

width = x ft

Length = 8x

Area of rectangle = 72 sq.feet

length * width = 72

8x * x = 72

8x² = 72

x² = 72/8

x² = 9 = 3²

x = 3

Width = x = 3 feet

Length = 8x = 8*3 = 24 feet

Perimeter = 2*(length + width)

= 2*(24 + 3) = 2*27 = 54 feet