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What are the real or imaginary solutions of 2x+7X? = 15x7

A. 0, , -5
B. 0,-1,5
C. 15
D. 0, -3,5

User TJ Weems
by
6.2k points

1 Answer

5 votes

Answer:

x=0 x=(3/5)^1/6

Explanation:

2x+7X? = 15x7

Combine like terms

9x = 15 x^7

Subtract 9x from each side

9x-9x = 15x^7 -9x

0 = 15x^7 -9x

Factor out 3x

0 =3x(5x^6 -3)

Using the zero product property

3x= 0 5x^6 -3 =0

x=0 5x^6 =3

x^6 = 3/5

Take the sixth root

x = (3/5)^1/6

User Jorzel
by
7.3k points