Question

Which is an equation of the line containing the points (4, 10) and (6, 11) in standard form?

A. –x + 2y = 16

B. x + 2y = 24

C. x – 2y = –16

D. 2x – y = –2

Answer 1

THE OTHER GUY IS WRONG OMG

Explanation:

Answer 2

Option C, x - 2y = -16

Explanation:

Step 1: Find the slope

`m = (y_2 - y_1) / (x_2 - x_1)`

`m = (11 - 10) / (6 - 4)`

`m = 1 / 2`

Step 2: Plug in into point-slope form

`(y - y_1) = m(x - x_1)`

`(y - 10) = 1/2(x - 4)`

`y - 10 = 1/2x - 2`

Step 3: Solve for x

`y - 10 + 2 = 1/2x - 2 + 2`

`(y - 8) * 2/1 = 1/2x * 2/1`

`2y - 16 = x`

Step 3: Put the variables on one side

`2y - 16 - 2y = x - 2y`

`-16 = x - 2y`

`x - 2y = -16`

Answer: Option C, x - 2y = -16