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3 votes
Evaluate 7C3
OA) 25
O B) 45
OC) 35
OD) 20

Evaluate 7C3 OA) 25 O B) 45 OC) 35 OD) 20-example-1
User Gus E
by
6.1k points

2 Answers

2 votes

Answer:

C) 35

Explanation:


^7C_3 \\ = (7!)/(3!(7 - 3)!) \\= (7!)/(3! \: 4!) \\ = (7 * 6 * 5 * 4!)/(3 * 2 * 1 * 4!) \\ = (7 * 6 * 5 * 4!)/(3 * 2 * 1 * 4!) \\ = 35 \\ \huge \red{ \boxed{ \therefore \: ^7C_3 = 35}}

User Steve Murdock
by
5.8k points
7 votes

Answer:

C=35

Explanation:

⁷C₃

These is combination

using the rule it states that

ⁿCₐ= n!/(n-a)!a!

so therefore ⁷C₃= 7!/(7-3)!3! = 7!/4!3!=7x6x5x4x3x2x1/{(4x3x2x1)x(3x2x1)}

4x3x2x1 cancels itself as it appears up and down

7x6x5/6

6 cancels each itself as it appears up and down

7x5 = 35

User Plamen Tetevensky
by
6.2k points