Answer:
(0, - 3 ) and (2, 1 )
Explanation:
Given the 2 equations
y = 2x - 3 → (1)
y = x² - 3 → (2)
Substitute y = x² - 3 into (1)
x² - 3 = 2x - 3 ( subtract 2x - 3 from both sides )
x² - 2x = 0 ← factor out x from each term
x(x - 2) = 0
Equate each factor to zero and solve for x
x = 0
x - 2 = 0 ⇒ x = 2
Substitute these values into (1) for corresponding values of y
x = 0 : y = 2(0) - 3 = 0 - 3 = - 3 ⇒ (0, - 3 )
x = 2 : y = 2(2) - 3 = 4 - 3 = 1 ⇒ (2, 1 )