Answer:
(3b + c)(a - 2b)
Explanation:
Given
3ab - 6b² - 2bc + ac ← Rearranging
= 3ab + ac - 6b² - 2bc (factor the first/second and third/fourth terms )
= a(3b + c) - 2b(3b + c) ← factor out (3b + c) from each term
= (3b + c)(a - 2b)
(a-2b)(3b-c)
3ab-6b^2-2bc+ac
Let's rearrange
3ab+ac-6b^2-2bc
Let's factorise
a(3b+c)-2b(3b+c)
(a-2b)(3b+c)
Since the answer cannot be solved further
The answer is (a-2b)(3b+c)
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