... The area between the x-axis & y=x² – 3x² + 2x 0 0 \leqslant x \leqslant 2 ​

Question

... The area between the x-axis & y=x² – 3x² + 2x 0


`0 \leqslant x \leqslant 2`
​

Answer 1

Explanation:

hello :

calculate :F(x) = ∫(x²-3x+2)dx

F(x) = (1/3)x^3 -(3/2)x² +2x

the area is :A = F(1)-F(0)

F(1) = (1/3)1^3 -(3/2)1² +2(1) =5/6

F(0) =0

so A= 5/6 Uof area