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a mountain bike tire has a diameter of 26 inches to the nearest foot how far does the tire travel when it makes 32 revolutions and does this require circumference and area?

User Galt
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1 Answer

5 votes

The distance it covers in 32 revolution is 217.9 ft .

Explanation:

Given,

The diameter of the tire of the bike = 26 in

The radius (r) = 13 in

To find the distance it travels in 32 revolutions.

To find the revolution we need to find the circumference.

Formula

The circumference of a circle = 2πr

Now,

The circumference of a circle = 2×
(22)/(7)×13 in

= 81.71 in (approx)

The distance it covers in 32 revolution is = 81.71×32 in

= 2614.85 in

We know that 1 ft = 12 inch

2614.85 in = 2614.85 ÷ 12 ft = 217.9 ft (approx)

User Aggietech
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6.8k points