Question

A calorimeter contains 0.50 kg of water at 15°C. A 0.040-kg block of zinc at 115°C is placed in the water. The specific heat of zinc is 388 J/kg °C and the specific heat of water is 4184 J/kg °C

What is the final temperature of the system?

Answer 1

The final temperature is 16°C

Step-by-step explanation:

mcΔT (water) = mcΔT (zinc)

0.50(4184)(t-15) = 0.040(388)(115-t)

2092(t-15) = 15.52(115-t)

2092t-31380 = 1784.8-15.52t

2029t+15.52t= 1784.8+31380

2044.52t = 33164.8

t = 33164.8/2044.52

t = 16