37.7k views
4 votes
A coin is tossed two times, then a month of the year is randomly selected. What is the probability of getting tails each time, and a month that starts with the letter J? I got 1/8 is that correct if not what’s the answer

User Kasey
by
7.6k points

2 Answers

1 vote

Answer:

1/16

Explanation:

Given a fair coin, the probability of getting tails on any one toss =

P(tails) = 1/2

if a coin is tossed twice and we get tails both times,

P( 2 tails on 2 consecutive tosses) = (1/2)(1/2) = 1/4

Total number of months = 12 months

Months that start with J = January, June, July = 3 months

P(selecting months that start with J) = 3/12 = 1/4

Hence the probability of tossing 2 consecutive tails then selecting a month that starts with J

= (1/4) x (1/4)

= 1/16

User Abhishek Ginani
by
8.7k points
5 votes

Answer:

1/16

Explanation:

1/2 getting tails

1/4 getting tails twice

3/12 getting a J month =1/4

1/4 x 1/4 =1/16

User Efreed
by
8.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories