Question

No one helped me, i need this urgently :(((
trinomials method can i have some help?

Answer 1

#1

• 2x²+x-6
• 2x²+4x-3x-6
• 2x(x+2)-3(x+2)
• (2x-3)(x+2)

#2

• 10a²+3a-1
• 10a²+5a-2a-1
• 5a(2a+1)-1(2a+1)
• (5a-1)(2a+1)

#3

• 2c²+5c-12
• 2c²+8c-3c-12
• 2c(c+4)-3(c+4)
• (2c-3)(c+4)

Answer 2

a: 3/2, -2 b: 1/5, -1/2 c: 3/2, -4

Explanation:

a: 2x^2+x=6

Subtract 6 from both sides.

2x^2+x−6=6−6

2x^2+x−6=0

Factor left side of equation.

(2x−3)(x+2)=0

Set factors equal to 0.

2x−3=0 or x+2=0

b: 10a^2+3a=1

Subtract 1 from both sides.

10a^2+3a−1=1−1

10a^2+3a−1=0

Factor left side of equation.

(5a−1)(2a+1)=0

Set factors equal to 0.

5a−1=0 or 2a+1=0

c: 2c^2+5c=12

Subtract 12 from both sides.

2c^2+5c−12=12−12

2c^2+5c−12=0

Factor left side of equation.

(2c−3)(c+4)=0

Set factors equal to 0.

2c−3=0 or c+4=0