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Find an equation for the line that passes through the points (-3,-2) and (1,4)

User Cathleen
by
2.5k points

2 Answers

4 votes

Answer:

y + 2 = (3/2) (x+3) (point slope form)

Explanation:

(see attached for reference)

Given

(x₁, y₁) = (-3,-2)

(x₂, y₂) = (1,4)

Since we are given 2 points, it would be easiest to express the equation of the line in point-slope form (see attached)

(y - y₁) = m (x - x₁)

we already have the values for x₁ and y₁, hence we only need to find the slope m (see 2nd attached graphic)

m = (y₂-y₁) / (x₂ - x₁)

= [4 - (-2) ] / [1 - (-3)]

= (4+2) / (1+3)

= 6/4

= 3/2

substituting the value for m and the values for x₁ and y₁:

(y - y₁) = m (x - x₁)

[y - (-2)] = (3/2) [x - (-3)]

y + 2 = (3/2) (x+3)

Find an equation for the line that passes through the points (-3,-2) and (1,4)-example-1
Find an equation for the line that passes through the points (-3,-2) and (1,4)-example-2
User Tomas Chabada
by
3.8k points
4 votes

Answer:

y=2/3x

Explanation:

First, we have to find the slope, which is
((y_(1) -y_(2)))/((x_(1)-x_(2))

(-3-1)/(-2-4)

-4/-6

2/3 is slope.

y=2/3x+-___

substitute in -3 from first point

y=-2+__=-2

y=2/3x+0

y=2/3x

User Slemgrim
by
3.8k points