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Calculate OH- given .010 M h+

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Answer:

(OH-)=1x10^-12 M

Step-by-step explanation:

Both pH and pOH have a relationship to belonging to the same aqueous solution: the expression of the Kwater (ionic product of the water Kw) is used:

(H3O+) x (OH-) = 1x10^-14

(0,010) x (OH-)= 1x10^-14

(OH-)=1x10^-14/(0,010)

(OH-)=1x10^-12 M

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