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How many mL of 3.0M HCl are needed to make 300.0 mL of a 0.10M HCl?

a
0.001 mL
b
none of the above
c
10 mL
d
0.10 mL

User Livea
by
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1 Answer

4 votes

Answer:

V₁ = 10 mL

Step-by-step explanation:

Given data:

Initial volume of HCl = ?

Initial molarity = 3.0 M

Final molarity = 0.10 M

Final volume = 300.0 mL

Solution:

Formula:

M₁V₁ = M₂V₂

M₁ = Initial molarity

V₁ = Initial volume of HCl

M₂ =Final molarity

V₂ = Final volume

Now we will put the values.

3.0 M ×V₁ = 0.10 M×300.0 mL

3.0 M ×V₁ = 30 M.mL

V₁ = 30 M.mL /3.0 M

V₁ = 10 mL

User Guffa
by
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