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Find the volume of a right circular cone that has a height of 5.3 fr and a base with a circumference of 19.1 ft. Round your answer to the nearest tenth of a cubic foot.

2 Answers

2 votes

Answer:

51.3 ft^3

Explanation:

User NooBskie
by
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3 votes

For this case we have that by definition, the volume of a cone is given by:


V = \frac {1} {3} * \pi * r ^ 2 * h

Where:

r: It is the radius of the cone

h: Is the height of the cone

We must find the radius knowing that the circumference of the base of the cone is
19.1 \ ft


2 \pi * r = 19.1\\r = \frac {19.1} {2 \pi}\\r = 3.04 \ ft

Thus, we substitute in the formula:


V = \frac {1} {3} * \pi * (3.04) ^ 2 * 5.3\\V = \frac {1} {3} * \pi * 9.25 * 5.3\\V = \frac {1} {3} * 154.0165\\V = 51.34

Thus, the volume of the cone is:
51.34 \ ft ^ 3

Answer:


51.3 \ ft ^ 3

User Pardahlman
by
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