Answer:
Mass of the sphere is 19.2 kg
Step-by-step explanation:
We have given diameter of the sphere d = 0.74 m
So radius r = 0.37 m
Initial angular velocity
![\omega _i=0rad/sec](https://img.qammunity.org/2021/formulas/physics/college/3dbetlfdd57z2fb2p1rxmhltnsdrv0cpxv.png)
Time t = 14 sec
Angular displacement
![\Theta =160revolution=160* 2\pi =1004.8rad](https://img.qammunity.org/2021/formulas/physics/college/ssb829rlt16ds3soj02sm7c8wojql9kk0j.png)
From second equation of motion
![\Theta =\omega _it+(1)/(2)\alpha t^2](https://img.qammunity.org/2021/formulas/physics/college/8ubct02c7y8xycda5t2atqtz7kgznjah54.png)
So
![1004.8=0* t+(1)/(2)* \alpha * 14^2](https://img.qammunity.org/2021/formulas/physics/college/k3pvsp56m5rrg190m1xlhbdk0o8q9bm9mc.png)
![\alpha =10.25rad/sec^2](https://img.qammunity.org/2021/formulas/physics/college/hlb5m4767nt8wiqvegilboe4m68hm0rp42.png)
Torque is given
![\tau =10.8Nm](https://img.qammunity.org/2021/formulas/physics/college/31z52mlp7krn7wwes7v6a6qo5b2vv8e0x4.png)
Torque is equal to
, here I is moment of inertia and
angular acceleration
So
![10.8=10.25* I](https://img.qammunity.org/2021/formulas/physics/college/7xekxvo7clwgntn558tgnm5a6gadiescyg.png)
![I=1.053kgm^2](https://img.qammunity.org/2021/formulas/physics/college/poqj7y9ybp9tv5u9np0itxes9u4ctmdtal.png)
Moment of inertia of sphere is equal to
![I=(2)/(5)Mr^2](https://img.qammunity.org/2021/formulas/physics/college/25xupqdmd02c58cn91evv43yrsbk5eh1ex.png)
So
![1.053=(2)/(5)* M* 0.37^2](https://img.qammunity.org/2021/formulas/physics/college/vesqlisjq66odjc1uos95eahkablgccyhn.png)
M = 19.23 kg
So mass of the sphere is 19.23 kg