Answer:
321 g
Step-by-step explanation
All you need to know here is that the molarity of a solution tells you the number of moles of solute present in exactly
1 L
of the solution.
In your case, a
2.20-M
sodium chloride solution will contain
2.20
moles of sodium chloride, the solute, for every
1 L
of the solution.
So if every
1 L
of this solution must contain
2.20
moles of sodium chloride in order for the solution to have a molarity of
2.20 M
, it means that
2.50 L
of this solution must contain
2.50
L solution
⋅
2.20 moles NaCl
1
L solution
=
5.50 moles NaCl
To convert the number of moles of sodium chloride to grams, use the molar mass of the compound.
5.50
moles NaCl
⋅
58.4 g
1
mole NaCl
=
321 g
−−−−−
The answer is rounded to three sig figs.