Answer:
1.2 volt induced in coil.
Step-by-step explanation:
Given:
Number of turns

Cross sectional area

Rate of increasing magnetic field

From the faraday's law,
Induced emf is given by,

Where
magnetic flux
( because angle between normal coil and field is zero)
Where
area of coil
Put the value of
in above equation,
Here we neglect minus sign


V
Therefore, 1.2 volt induced in coil