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F the angle of elevation from the point on the ground to the top of the tree is 34° and the point is 25 feet from the base of the tree, what is the height of the tree (to the nearest tenth of a foot)?

A) 14.0 feet
B) 16.9 feet
C) 19.3 feet
D) 20.7 feet

User Mikeck
by
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2 Answers

1 vote

Answer:

16.9 feet

Explanation:

User Minglyu
by
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3 votes

Given:

The angle of elevation from the point on the ground to the top of the tree is 34° and the point is 25 feet from the base of the tree.

We need to determine the height of the tree.

Height of the tree:

Let the height of the tree be h.

The height of the tree can be determined using the trigonometric ratio.

Thus, we have;


tan \ \theta=(opp)/(adj)

Substituting the values, we get;


tan \ 34^(\circ)=(h)/(25)

Multiplying both sides by 25, we have;


tan \ 34^(\circ) * 25=h


0.6745 * 25=h


16.8625=h

Rounding off to the nearest tenth of a foot, we get;


16.9=h

Thus, the height of the tree is 16.9 feet.

Hence, Option B is the correct answer.

User Peter Badida
by
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